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1009. Product of Polynomials
1009. Product of Polynomials (25)
This time, you are supposed to find A*B where A and B are two polynomials.
Input Specification:
Each input file contains one test case. Each case occupies 2 lines, and each line contains the information of a polynomial: K N1 aN1 N2 aN2 ... NK aNK, where K is the number of nonzero terms in the polynomial, Ni and aNi (i=1, 2, ..., K) are the exponents and coefficients, respectively. It is given that 1 <= K <= 10, 0 <= NK < ... < N2 < N1 <=1000.
Output Specification:
For each test case you should output the product of A and B in one line, with the same format as the input. Notice that there must be NO extra space at the end of each line. Please be accurate up to 1 decimal place.
Sample Input2 1 2.4 0 3.22 2 1.5 1 0.5Sample Output
3 3 3.6 2 6.0 1 1.6
1 #include<stdio.h> 2 #include<math.h> 3 #include<stdlib.h> 4 #include<string.h> 5 6 int main() 7 { 8 double a[1010] = {}, b[1010] = {}, ans[2010] = {}; 9 int ka, kb, i, j, x, y, maxa, maxb;10 scanf("%d", &ka);11 scanf("%d", &x);12 scanf("%lf", &a[x]);13 maxa = x;14 for(i = 1; i < ka; i++)15 {16 scanf("%d", &x);17 scanf("%lf", &a[x]);18 }19 scanf("%d", &kb);20 scanf("%d", &y);21 scanf("%lf", &b[y]);22 maxb = y;23 for(i = 1; i < kb; i++)24 {25 scanf("%d", &y);26 scanf("%lf", &b[y]);27 }28 int max = 0;29 if(maxa > maxb)30 {31 for(i = maxa; i >= 0; i--)32 {33 for(j = maxb; j >= 0; j--)34 {35 ans[i + j] += a[i] * b[j];36 if((i + j) > max)37 {38 max = i + j;39 }40 }41 }42 }43 else44 {45 for(i = maxb; i >= 0; i--)46 {47 for(j = maxa; j >= 0; j--)48 {49 ans[i + j] += b[i] * a[j];50 if((i + j) > max)51 {52 max = i + j;53 }54 }55 }56 }57 int count = 0;58 for(i = max; i >= 0; i--)59 {60 if(ans[i] != 0)61 count++;62 }63 printf("%d", count);64 for(i = max; i >= 0; i--)65 {66 if(ans[i] != 0)67 {68 printf(" %d %.1f", i, ans[i]);69 }70 }71 printf("\n");72 return 0;73 }
1009. Product of Polynomials