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Codility---MaxProductOfThree
Task description
A non-empty zero-indexed array A consisting of N integers is given. Theproduct of triplet (P, Q, R) equates to A[P] * A[Q] * A[R] (0 ≤ P < Q < R < N).
For example, array A such that:
A[0] = -3 A[1] = 1 A[2] = 2 A[3] = -2 A[4] = 5 A[5] = 6contains the following example triplets:
- (0, 1, 2), product is −3 * 1 * 2 = −6
- (1, 2, 4), product is 1 * 2 * 5 = 10
- (2, 4, 5), product is 2 * 5 * 6 = 60
Your goal is to find the maximal product of any triplet.
Write a function:
class Solution { public int solution(int[] A); }
that, given a non-empty zero-indexed array A, returns the value of the maximal product of any triplet.
For example, given array A such that:
A[0] = -3 A[1] = 1 A[2] = 2 A[3] = -2 A[4] = 5 A[5] = 6the function should return 60, as the product of triplet (2, 4, 5) is maximal.
Assume that:
- N is an integer within the range [3..100,000];
- each element of array A is an integer within the range [−1,000..1,000].
Complexity:
- expected worst-case time complexity is O(N*log(N));
- expected worst-case space complexity is O(1), beyond input storage (not counting the storage required for input arguments).
Elements of input arrays can be modified.
Solution
Programming language used: Java
Total time used: 14 minutes
Code: 00:27:07 UTC, java, final, score: 100
show code in pop-up
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// you can also use imports, for example:// import java.util.*;// you can write to stdout for debugging purposes, e.g.// System.out.println("this is a debug message");import java.util.Arrays;import java.lang.Math;class Solution { public int solution(int[] A) { // write your code in Java SE 8 Arrays.sort(A); int res = A[0] * A[1] * A[2]; res = Math.max(res, A[0] * A[1] *A[A.length-1]); res = Math.max(res, A[0] * A[A.length-1] *A[A.length-2]); res = Math.max(res, A[A.length-3] * A[A.length-1] *A[A.length-2]); return res; }}
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Codility---MaxProductOfThree
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