首页 > 代码库 > 拼接sql
拼接sql
String whereArgs = taskTable + " where 1=1 ";
if (upCheck) {
whereArgs += " and type = 2 ";
}
if (gameID != null && !gameID.equals("0")) {
whereArgs += " and gameID = " + gameID;
}
if (searchProjectkey != null && !searchProjectkey.trim().equals("")) {
whereArgs += " and projectID like " + "‘%" + searchProjectkey
+ "%‘";
}
if (searchChannelkey != null && !searchChannelkey.trim().equals("")) {
whereArgs += " and channelName like " + "‘%" + searchChannelkey
+ "%‘";
}
拼接sql
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。