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Developer Test-Java

2024-09-30 11:35:02   215人阅读

Java

    1. Give two String, write a method  to decide if one is a permutation of the other.

  for example: string s1="dog" string s2="god" is true; string  s3="dgo" is also true;

public boolean isPermutation(String s1,String s2){
         boolean flag=false;
         if(s1.length()==0 && s1.length()!=s2.length()){
             flag = false;
         }else {
             String str1=new String(s1);
             String str2=new String(s2);
             char[] str1ToChar=s1.toCharArray();
             char[] str2ToChar=s2.toCharArray();
              Arrays.sort(str1ToChar);
              Arrays.sort(str2ToChar);
             if(Arrays.equals(str1ToChar,str2ToChar)){
                 flag = true;
             }
         }
         return flag;
   }

 2. F(0)=0;F(1)=0; F(n)=F(n-1)+F(n-2) for n>1(递归)

 

public int recursion(int n){
        if(n==1 || n==2){
            n=1;
        }else{
            n=recursion(n-1)+recursion(n-2);
        }
        return n;
  }

 

Developer Test-Java


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