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LeetCode OJ - Insertion Sort List
题目:
Sort a linked list using insertion sort.
解题思路:
假设 list[1..i]是排好序的,找到第i+1个元素应该插入的位置及其前驱,然后将其插入。
代码:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode *insertionSortList(ListNode *head) { if (head == NULL || head->next == NULL) { return head; } /*找到最小的元素作为表头*/ ListNode *p_tmp = head; int min_val = head->val; ListNode *p_current = head->next; while (p_current != NULL) { if (p_current->val < min_val) { p_tmp = p_current; min_val = p_current->val; } p_current = p_current->next; } p_tmp->val = head->val; head->val = min_val; //////////////////////////////////////////////////////// p_current = head->next; while (p_current != NULL){ ListNode *p_next = p_current->next; ListNode *p_pos = head; //找插入位置 while (p_pos != p_current && p_pos->next->val <= p_current->val) p_pos = p_pos->next; ListNode *p_pre = head; // 找前驱 while (p_pre->next != p_current) p_pre = p_pre->next; if (p_pos != p_current) { p_pre->next = p_current->next; p_current->next = p_pos->next; p_pos->next = p_current; } p_current = p_next; } return head; } };
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