# 输入客户带出它默认的发运方式和包装方式
def on_change_partner_id_return(self,cr,uid,ids,partner_id,context=None):
    result={}
    if partner_id:# 如果存在
     #找到满足条件的值
        obj=self.pool.get(‘res.partner‘).browse(cr,uid,partner_id,context=context)
        #取出数据显示在前端
        fyfs=obj.send_type
        zxbzfs=obj.packing_type
        khmc=obj.name
        # 返回结果
        result[‘send_invoice_type‘]=fyfs
        result[‘packing_type‘]=zxbzfs
        print khmc
       数据库查询语句,查出历史订单中的产品,去除重复数据
      
        sql="select DISTINCT t2.product_id as product_id, t6.material as material,t6.cust_spec as cust_spec,t6.list_price as price,t4.name as uom, t3.packing_type1 as pick_type  from  res_partner  t0  LEFT JOIN sale_order t1  on  t0.id=t1.partner_id  LEFT JOIN sale_order_line t2  on t2.order_id=t1.id LEFT JOIN sale_origin_line t3 on  t2.order_id=t3.order_id LEFT JOIN product_uom t4 on t4.id=t2.product_uom  left join product_product t5 on t5.id=t2.product_id left join product_template t6 on t6.id=t5.product_tmpl_id where  t1.partner_id is not null and  t0.name=‘%s‘"%(khmc)
        
        print 555555555555555555555
        history_line=[]
       
遍历将数据打印到前端
        for i in range(len(dict)):
          print dict[i]
          # history_line=[]
          history_line.append({‘hproduct_id‘:dict[i][‘product_id‘] ,
                                  ‘hmaterial‘:dict[i][‘material‘],
                                  ‘hspec‘:dict[i][‘cust_spec‘],
                                  ‘hproduct_uom‘:dict[i][‘uom‘],
                                  ‘hprice‘:dict[i][‘price‘],
                                  ‘hpacking_type1‘:dict[i][‘pick_type‘]
                                  })
        result[‘history_order_line‘]=history_line
        print 1111111111111111111111111111111111111111
        print history_line
        return {‘value‘:result}










如图中 根据客户名称带出历史订单产品

odoo之带出历史订单产品