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分子量(Molar Mass UVa1586)

题目来自张汝佳的《算法竞赛入门经典(第二版)》

题目描述:

技术分享

 

我的代码:

#include<iostream>
#include<cstring>
#include <iomanip>
using namespace std;
#define C 12.01
#define H 1.008
#define O 16.00
#define N 14.01
int main() 
{
    int i, k;
    char enter[1000];
    cin >> k;
    while (k--)
    {        
        cin >> enter;
        double tot = 0.0;
        int num = 0, j;
        double ans = 0;
        for (i = 0; i < strlen(enter); i++) 
        {
            ans = 0;
            switch (enter[i])
            {
            case C:
                num = 0;                    
                if (enter[i + 1] <= 9 && enter[i + 1] >= 0)
                {
                    i++;
                    while (enter[i] <= 9 && enter[i] >= 0)
                    {
                        if (num == 0)
                            num = i;
                        i++;
                    }

                    for (j = i; num < j; num++)
                        ans += ((double)(enter[num] - 0) * pow(10, j - num - 1));

                    tot += ans * C;
                    i--;
                }
                else
                    tot += C;
                break;
            case H:
                num = 0;
                if (enter[i + 1] <= 9 && enter[i + 1] >= 0)
                {
                    i++;
                    while (enter[i] <= 9 && enter[i] >= 0)
                    {
                        if (num == 0)
                            num = i;
                        i++;
                    }

                    for (j = i; num < j; num++)
                        ans += ((double)(enter[num] - 0) * pow(10, j - num - 1));

                    tot += ans * H;
                    i--;
                }
                else
                    tot += H;
                break;
            case O:
                num = 0;
                if (enter[i + 1] <= 9 && enter[i + 1] >= 0)
                {
                    i++;
                    while (enter[i] <= 9 && enter[i] >= 0)
                    {
                        if (num == 0)
                            num = i;
                        i++;
                    }

                    for (j = i; num < j; num++)
                        ans += ((double)(enter[num] - 0) * pow(10, j - num - 1));

                    tot += ans * O;
                    i--;
                }
                else
                    tot += O;
                break;
            case N:
                num = 0;
                if (enter[i + 1] <= 9 && enter[i + 1] >= 0)
                {
                    i++;
                    while (enter[i] <= 9 && enter[i] >= 0)
                    {
                        if (num == 0)
                            num = i;
                        i++;
                    }

                    for (j = i; num < j; num++)
                        ans += ((double)(enter[num] - 0) * pow(10, j - num - 1));

                    tot += ans * N;
                    i--;
                }
                else
                    tot += N;
                break;
            }
        }
        cout << setiosflags(ios::fixed) << setprecision(3) << tot << "g/mol" << endl;
    }
    return 0;
}

 

Sample Input



C6H5OH 
NH2CH2COOH 
C12H22O11 


Sample Output

12.010 
94.108 
75.070 
342.296

水题,但是有陷阱,所以特地放了上来╮(╯▽╰)╭,求大神们更好的代码~

分子量(Molar Mass UVa1586)