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为女票写的计算工作时间的SQL

排除非工作时间、非工作日后,计算工作时间,代码如下:

-- 删除函数DROP FUNCTION IF EXISTS calculateWorkingTime;set @workStartTime=‘09:30:00‘; set @workEndTime=‘18:30:00‘; -- 创建函数--/CREATE FUNCTION calculateWorkingTime(startDate datetime,endDate datetime)RETURNS decimal(32,4)BEGIN  DECLARE intnum int(255) DEFAULT 0;  DECLARE decimalnum decimal(32,4) DEFAULT 0.000;  DECLARE workStartTimeHour decimal(32,4) DEFAULT 0.000;  DECLARE workEndTimeHour decimal(32,4) DEFAULT 0.000;  DECLARE currentDay int(10) DEFAULT 0;  DECLARE tempTimeHour decimal(32,4) DEFAULT 0.000;  -- DECLARE temp varchar(2048) DEFAULT ‘‘;    -- deal starttime and endtime is nonworkdays  SET startDate = (CASE WHEN weekday(startDate)=5 THEN concat(date(timestampadd(day,2,startDate)),‘ ‘,@workStartTime) WHEN weekday(startDate)=6 THEN concat(date(timestampadd(day,1,startDate)),‘ ‘,@workStartTime) ELSE startDate END);  SET endDate = (CASE WHEN weekday(endDate)=5 THEN concat(date(timestampadd(day,-1,endDate)),‘ ‘,@workEndTime) WHEN weekday(endDate)=6 THEN concat(date(timestampadd(day,-2,endDate)),‘ ‘,@workEndTime) ELSE endDate END);--  SET temp = concat(temp,‘ ‘,startDate,‘;‘,endDate);   if startDate < endDate then    -- deal starttime and endtime is nonworktime    if time(startDate)<=@workStartTime THEN       SET startDate = concat(date(startDate),‘ ‘, @workStartTime);    elseif date(startDate) < date(endDate) and time(startDate)>@workEndTime then        SET startDate = concat(date(date_add(startDate, interval 1 day)),‘ ‘,@workStartTime);    end if;        if time(endDate)>=@workEndTime then      SET endDate = concat(date(endDate),‘ ‘,@workEndTime);    elseif date(startDate) < date(endDate) and time(endDate)<@workStartTime then        SET endDate = concat(date(date_add(endDate, interval -1 day)),‘ ‘,@workEndTime);    end if;        -- calculate time diff    SET decimalnum = (minute(endDate)*60+second(endDate)-minute(startDate)*60-second(startDate))/3600;      end if;    -- calculate work time second  SET workStartTimeHour = hour(@workStartTime)+minute(@workStartTime)/60+second(@workStartTime)/3600;  SET workEndTimeHour = hour(@workEndTime)+minute(@workEndTime)/60+second(@workEndTime)/3600;    --  WHILE (floor((unix_timestamp(endDate) - unix_timestamp(startDate))/3600) > 0) DO WHILE ((floor(unix_timestamp(endDate)/3600) - floor(unix_timestamp(startDate)/3600)) > 0) DO     SET tempTimeHour = hour(startDate)+minute(startDate)/60+second(startDate)/3600;          if   workStartTimeHour <= tempTimeHour and tempTimeHour < workEndTimeHour then    --   SET temp = concat(temp,‘ ‘,tempTimeHour,‘;‘);       SET intnum = (CASE WHEN weekday(startDate)=5 or weekday(startDate)=6 then intnum ELSE intnum+1 END);     end if;     SET startDate = timestampadd(hour,1,startDate);   END WHILE;     SET decimalnum = intnum + decimalnum;  -- concat(decimalnum,‘;‘,workStartTimeHour,‘ ‘,workEndTimeHour,‘ ‘,intnum,‘;;;‘,temp);  RETURN decimalnum;END /-- select calculateWorkingTime(‘2017-02-17 07:30:00‘,‘2017-02-21 17:39:00‘);select transport_id,create_at1,create_at2,create_at3, calculateWorkingTime(create_at1,create_at2), calculateWorkingTime(create_at2,create_at3),calculateWorkingTime(create_at1,create_at3) from newTable;select transport_id,calculateWorkingTime(create_at1,create_at2) from newTable;

    说明:第一次实现这种需求,当初写的时候又比较赶,写完后,发现,虽然功能实现了,但还有好多地方可以调优 

            女票是搞数据运营的,经常需要统计员工的工作时间;听女票说,这段SQL代码统计时好像有些问题,但还没来的急分析原因呢;女票又有新需求来了,不仅需要将非工作时间、非工作日去掉,还需要将节假日去掉   我将上面代码重构,实现想要功能(重构后的代码就不放出了)

 

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为女票写的计算工作时间的SQL