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HDU 2212 DFS【列举题】
将数列举出就可以了
DFS
Time Limit: 5000/2000 MS (Java/Others)
Memory Limit: 65536/32768 K (Java/Others)
Problem Description
A DFS(digital factorial sum) number is found by summing the factorial of every digit of a positive integer.
For example ,consider the positive integer 145 = 1!+4!+5!, so it‘s a DFS number.
Now you should find out all the DFS numbers in the range of int( [1, 2147483647] ).
There is no input for this problem. Output all the DFS numbers in increasing order. The first 2 lines of the output are shown below.
For example ,consider the positive integer 145 = 1!+4!+5!, so it‘s a DFS number.
Now you should find out all the DFS numbers in the range of int( [1, 2147483647] ).
There is no input for this problem. Output all the DFS numbers in increasing order. The first 2 lines of the output are shown below.
Input
no input
Output
Output all the DFS number in increasing order.
Sample Output
1 2 ......
Author
zjt
#include<stdio.h> int main() { printf("1\n2\n145\n40585\n"); return 0; }
HDU 2212 DFS【列举题】
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