代码：

1. mtx.lock();
2. printf("node %d push localW prepared,and local flag=%d,clock=%d\n",procID,localW.getFlag(),localW.getClock());
3. printf("localQ is empty:%s\n",localQ.empty()?"true":"false");
4. localQ.push(localW);
5. printf("node %d push localW successfully,and front flag=%d,clock:%d\n",procID,localQ.front().getFlag(),localQ.front().getClock());
6. printf("node %d push localW successfully,and local flag=%d,clock:%d\n",procID,localW.getFlag(),localW.getClock());
7. mtx.unlock();

输出的结果就神奇了，给大家瞅瞅：

node 2 push localW prepared,and local flag=0,clock=0
localQ is empty:true
node 2 push localW successfully,and front flag=4,clock:24
node 2 push localW successfully,and local flag=0,clock:0

目前还未找到原因，找到原因我会更新。

C++ 队列queue中的一段玄学代码