首页 > 代码库 > LintCode-Longest Common Substring
LintCode-Longest Common Substring
Given two strings, find the longest common substring.
Return the length of it.
Note
The characters in substring should occur continiously in original string. This is different with subsequnce.
Solution:
1 public class Solution { 2 /** 3 * @param A, B: Two string. 4 * @return: the length of the longest common substring. 5 */ 6 public int longestCommonSubstring(String A, String B) { 7 int lenA = A.length(); 8 int lenB = B.length(); 9 if (lenA==0 || lenB ==0 ) return 0;10 11 int[][] lcs = new int[lenA+1][lenB+1];12 for (int i=0;i<=lenA;i++) lcs[i][0] = 0;13 for (int i=0;i<=lenB;i++) lcs[0][i] = 0;14 15 int res = 0;16 for (int i=1;i<=lenA;i++)17 for (int j=1;j<=lenB;j++)18 if (A.charAt(i-1)==B.charAt(j-1)){19 lcs[i][j]=lcs[i-1][j-1]+1;20 if (lcs[i][j]>res) res = lcs[i][j];21 } else lcs[i][j]=0;22 23 return res;24 }25 }
LintCode-Longest Common Substring
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。