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leetcode-Set Matrix Zeroes
Set Matrix Zeroes Total Accepted: 25064 Total Submissions: 80609 My Submissions Question Solution
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
click to show follow up.
Follow up:
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
click to show follow up.
Follow up:
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
class Solution {
public:
void setZeroes(vector<vector<int> > &matrix) {
int row1=1;
int col1=1;
int m=matrix.size();
int n=matrix[0].size();
//扫描第一行
for(int j=0;j<n;j++)
if(matrix[0][j]==0)
row1=0;
for(int i=0;i<m;i++)
if(matrix[i][0]==0)
col1=0;
//扫描余下矩阵
for(int i=1;i<m;i++)
{
for(int j=1;j<n;j++)
if(matrix[i][j]==0)
matrix[i][0]=matrix[0][j]=0;
}
//行置0
for(int i=1;i<m;i++)
if(matrix[i][0]==0)
for(int j=1;j<n;j++)
matrix[i][j]=0;
//列置0
for(int j=1;j<n;j++)
if(matrix[0][j]==0)
for(int i=1;i<m;i++)
matrix[i][j]=0;
//第一行置0
if(row1==0)
for(int j=0;j<n;j++)
matrix[0][j]=0;
//第一列置0
if(col1==0)
for(int i=0;i<m;i++)
matrix[i][0]=0;
}
};
leetcode-Set Matrix Zeroes
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