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HDU - 2368 Alfredo's Pizza Restaurant

题意:判断一个长方形是否能放到一个圆形里。

分析:将长方形的一条边贴近圆放置,求另一条边的最长长度lmax,若l<=lmax,则能放置。

注意:若这条边的长度大于直径,则一定不能放到圆里。因此,在求lmax的时候,在保证是非负数的情况下才能sqrt。

#include<cstdio>#include<cstring>#include<cstdlib>#include<cctype>#include<cmath>#include<iostream>#include<sstream>#include<iterator>#include<algorithm>#include<string>#include<vector>#include<set>#include<map>#include<stack>#include<deque>#include<queue>#include<list>#define lowbit(x) (x & (-x))const double eps = 1e-9;inline int dcmp(double a, double b){    if(fabs(a - b) < eps) return 0;    return a > b ? 1 : -1;}typedef long long LL;typedef unsigned long long ULL;const int INT_INF = 0x3f3f3f3f;const int INT_M_INF = 0x7f7f7f7f;const LL LL_INF = 0x3f3f3f3f3f3f3f3f;const LL LL_M_INF = 0x7f7f7f7f7f7f7f7f;const int dr[] = {0, 0, -1, 1, -1, -1, 1, 1};const int dc[] = {-1, 1, 0, 0, -1, 1, -1, 1};const int MOD = 1e9 + 7;const double pi = acos(-1.0);const int MAXN = 200000 + 10;const int MAXT = 10000 + 10;using namespace std;int main(){    double r, w, l;    int kase = 0;    while(scanf("%lf", &r) == 1){        if(dcmp(r, 0) == 0) return 0;        scanf("%lf%lf", &w, &l);        double lmax = r * r - (w / 2) * (w / 2);        if(dcmp(l * l / 4, lmax) <= 0){            printf("Pizza %d fits on the table.\n", ++kase);        }        else{            printf("Pizza %d does not fit on the table.\n", ++kase);        }    }    return 0;}

  

HDU - 2368 Alfredo's Pizza Restaurant