$a = ‘130424770827005‘;$reg18 = ‘/[1-9]\d{5}(((1[9|8])\d{2})|(20[0-1]\d))((0\d)|(1[0-2]))(([0|1|2]\d)|3[0-1])\d{3}([0-9]|X)/‘;$reg15 = ‘/[1-9]\d{7}((0\d)|(1[0-2]))(([0|1|2]\d)|3[0-1])\d{3}/‘;问题是对年份进行了判断从1800到2019
等4年就需要修改。
其实还可以更严格些。preg_match($reg15,$a,$mm);var_dump($mm);输出结果array (size=6)  0 => string ‘130424770827005‘ (length=15)  1 => string ‘08‘ (length=2)  2 => string ‘08‘ (length=2)  3 => string ‘‘ (length=0)  4 => string ‘27‘ (length=2)  5 => string ‘27‘ (length=2)