//no AC  //思路就是，第一个数+最后一个数+中间数字（分奇数和偶数）#include "stdio.h"#define MAX 10int main(void){	int i;	int num;	int sum;		//求和 	int score[MAX];		scanf("%d", &num);		while(num != 0){		for(i=0; i<num; i++){		//动态赋值 			scanf("%d", &score[i]);				}				for(i=0; i<num; i++){			if(num % 2 == 0){				sum = score[0] + score[num-1] + score[num/2] + score[num/2 - 1];			}						else{				sum = score[0] + score[num-1] + score[num/2];			}		} 				printf("%d\n", sum);		sum = 0;		}	return 0; }*//* *	 Result:Time Limit Exceeded *///解题思路，就是除去最后一个数字，其余数字相加#include "stdio.h"int main(void){	int i;	int j;	int num;	int sum = 0;		while(scanf("%d", &num), num){		//逗号后面的num,表示num的值，为0直接跳出循环。 		for(i=0; i<num; i++){			scanf("%d", &j);						sum += j;				}		printf("%d\n", sum);				sum = 0;	}	return 0;} /**	 Result:running	*/