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LeetCode-Merge Sorted Array
Given two sorted integer arrays A and B, merge B into A as one sorted array.
Note:
You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m andn respectively.
结题分析:当时想的是从前往后比较,A[]>B[],那么插入B[],A[]再往后移位。复杂度是(n^2)
后面才发现,可以从后往前。思路
class Solution { public: void merge(int A[], int m, int B[], int n) { int pointa = m-1; int pointb = n-1; for(int i = m+n-1; i >= 0; i--) { if(pointa == -1 ) A[i] = B[pointb--]; else if(pointb == -1 ) A[i] = A[pointa--]; else { if(A[pointa] > B[pointb]) A[i] = A[pointa--]; else A[i] = B[pointb--]; } } } };
不对真是害死人。
LeetCode-Merge Sorted Array
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