原题：

It is a well-known fact that behind every good comet is a UFO. These UFOs often come to collect loyal supporters from here on Earth. Unfortunately, they only have room to pick up one group of followers on each trip. They do, however, let the groups know ahead of time which will be picked up for each comet by a clever scheme: they pick a name for the comet which, along with the name of the group, can be used to determine if it is a particular group‘s turn to go (who do you think names the comets?). The details of the matching scheme are given below; your job is to write a program which takes the names of a group and a comet and then determines whether the group should go with the UFO behind that comet.

Both the name of the group and the name of the comet are converted into a number in the following manner: the final number is just the product of all the letters in the name, where "A" is 1 and "Z" is 26. For instance, the group "USACO" would be 21 * 19 * 1 * 3 * 15 = 17955. If the group‘s number mod 47 is the same as the comet‘s number mod 47, then you need to tell the group to get ready! (Remember that "a mod b" is the remainder left over after dividing a by b; 34 mod 10 is 4.)

Write a program which reads in the name of the comet and the name of the group and figures out whether according to the above scheme the names are a match, printing "GO" if they match and "STAY" if not. The names of the groups and the comets will be a string of capital letters with no spaces or punctuation, up to 6 characters long.

Examples:

COMETQ
HVNGAT

ABSTAR
USACO 

PROGRAM NAME: ride

This means that you fill in your header with:
PROG: ride 
WARNING: You must have ‘ride‘ in this field or the wrong test data (or no test data) will be used.

INPUT FORMAT

NOTE: The input file has a newline at the end of each line but does not have a "return". Sometimes, programmers code for the Windows paradigm of "return" followed by "newline"; don‘t do that! Use simple input routines like "readln" (for Pascal) and, for C/C++, "fscanf" and "fid>>string".

NOTE 2: Because of the extra characters, be sure to leave enough room for a ‘newline‘ (also notated as ‘\n‘) and an end of string character (‘\0‘) if your language uses it (as C and C++ do). This means you need eight characters of room instead of six.

SAMPLE INPUT (file ride.in)

COMETQ
HVNGAT

OUTPUT FORMAT

A single line containing either the word "GO" or the word "STAY".

SAMPLE OUTPUT (file ride.out)

GO

OUTPUT EXPLANATION

Converting the letters to numbers:

then calculate the product mod 47:

3 * 15 * 13 * 5 * 20 * 17 = 994500 mod 47 = 27
8 * 22 * 14 * 7 *  1 * 20 = 344960 mod 47 = 27

Because both products evaluate to 27 (when modded by 47), the mission is ‘GO‘. 

网址：http://train.usaco.org/usacoprob2?a=L06MbLFzLFN&S=ride

大意（自己翻译的）：

给出两个只含大写字母，长度小于等于6的字符串，如果它们最后转化成的数字对47取模后相等则输出“GO”，不然输出“STAY”。注意：输出的最后需要换行！

转化成的数字计算方法：将每个字母对应的数字（A对应1，B对应2...）相乘纪委这个字符串转化成的数字。

样例输入：

  COMETQ

  HVNGAT

样例输出：

  GO

有没有感觉翻译很水？叫你自己不学好英语！自己去原页面上看看就行了嘛！

题解（自己写的）：

就是简单的模拟，要注意吃回车：

getline(fin,s);

代码如下：

 1 /*
 2 ID:被和谐了
 3 PROB:ride
 4 LANG:C++
 5 */
 6 #include<bits/stdc++.h>
 7 using namespace std;
 8 
 9 string s;
10 int work(string x)
11 {
12     int t=1;
13     for (int i=0;i<x.length();i++) t*=x[i]-‘A‘+1,t%=47;
14     return t;
15 }
16 
17 int main()
18 {
19     int a,b;
20     
21     ifstream fin ("ride.in");
22     ofstream fout ("ride.out");
23 
24     getline(fin,s);
25     a = work(s);
26     getline(fin,s);
27     b = work(s);
28     if (a==b) fout<<"GO"; else fout<<"STAY";
29 
30     return 0;
31 }

有问题请联系作者，谢谢！

USACO Section 1.1 Your Ride Is Here