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136. Single Number
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution {public: int singleNumber(vector<int>& nums) { int ans = 0; vector<int>::const_iterator it = nums.cbegin(); for (; it != nums.cend(); ++it) { ans^=*it; } return ans; }};
136. Single Number
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