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LeetCode--Single Number
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution { public: int singleNumber(int A[], int n) { if(n==0) return -1; int res = A[0]; for(int i=1;i<n;i++) res = res^A[i]; return res; } };
LeetCode--Single Number
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