上篇文章介绍了什么是restful风格的webservice，本片文章通过一个demo着重介绍如何发布一个restful风格的web service.

1.建立接口

@Path(value = http://www.mamicode.com/"/sample")>
2.建立实现类
@Path(value = http://www.mamicode.com/"/sample")>
3.配置配置文件：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:jaxws="http://cxf.apache.org/jaxws"
    xmlns:jaxrs="http://cxf.apache.org/jaxrs"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/context
    http://www.springframework.org/schema/context/spring-context-3.0.xsd
    http://cxf.apache.org/jaxws 
    http://cxf.apache.org/schemas/jaxws.xsd
    http://cxf.apache.org/jaxrs
    http://cxf.apache.org/schemas/jaxrs.xsd">

	<import resource="classpath:META-INF/cxf/cxf.xml"/>
	<import resource="classpath:META-INF/cxf/cxf-extension-soap.xml"/>
	<import resource="classpath:META-INF/cxf/cxf-servlet.xml"/>
	<bean id="restSample" class="com.hoo.service.RESTSampleSource"/>
	<!-- 这里的地址很重要，客户端需要通过这个地址来访问WebService -->
	<jaxrs:server id="restServiceContainer" address="/rest">
	    <jaxrs:serviceBeans>
	        <ref bean="restSample" />
	    </jaxrs:serviceBeans>
	    <jaxrs:extensionMappings>
	        <entry key="json" value=http://www.mamicode.com/"application/json" />>
下面在浏览器中输入：http://localhost:8080/webservice，当出现如下效果时说明发布成功：
然后输入网址：http://localhost:8080/webservice/rest/sample/bean/123访问一下，看效果：
当出现上面的效果说明调用成功。

restful webservice实战