首页 > 代码库 > 121. Best Time to Buy and Sell Stock
121. Best Time to Buy and Sell Stock
Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction
(ie, buy one and sell one share of the stock), design an algorithm to find the maximum profit. Example 1: Input: [7, 1, 5, 3, 6, 4] Output: 5 max. difference = 6-1 = 5 (not 7-1 = 6, as selling price needs to be larger than buying price) Example 2: Input: [7, 6, 4, 3, 1] Output: 0 In this case, no transaction is done, i.e. max profit = 0.
本来想用栈, 发现只需要不断更新最小值和全局变量.
Algorithm
Say the given array is:
[7, 1, 5, 3, 6, 4]
If we plot the numbers of the given array on a graph, we get:
The points of interest are the peaks and valleys in the given graph. We need to find the largest peak following the smallest valley. We can maintain two variables - minprice and maxprofit corresponding to the smallest valley and maximum profit (maximum difference between selling price and minprice) obtained so far respectively.
public class Solution { public int maxProfit(int prices[]) { int minprice = Integer.MAX_VALUE; int maxprofit = 0; for (int i = 0; i < prices.length; i++) { if (prices[i] < minprice) minprice = prices[i]; else if (prices[i] - minprice > maxprofit) maxprofit = prices[i] - minprice; } return maxprofit; } }
121. Best Time to Buy and Sell Stock
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。