首页 > 代码库 > Add Two Numbers
Add Two Numbers
Add Two Numbers
You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Solution:
O(n) runtime, O(n) space – LinkedList
Use Linklist store val and pointer ! should pay attation to temp variable sentinel and d . especially return value .
1 public static ListNode addTwoNumbers(ListNode l1, ListNode l2) { 2 int sum = 0; 3 ListNode sentinel = new ListNode(0); 4 ListNode d = sentinel; 5 while (l1 != null || l2 != null) { 6 sum /= 10; 7 if (l1 != null) { 8 sum += l1.val; 9 l1 = l1.next;10 }11 if (l2 != null) {12 sum += l2.val;13 l2 = l2.next;14 }15 16 d.next = new ListNode(sum % 10);17 d = d.next;18 19 if(sum % 10 == 1)20 d.next = new ListNode(1);21 }22 return sentinel.next;23 }
Add Two Numbers
声明：以上内容来自用户投稿及互联网公开渠道收集整理发布，本网站不拥有所有权，未作人工编辑处理，也不承担相关法律责任，若内容有误或涉及侵权可进行投诉： 投诉/举报 工作人员会在5个工作日内联系你，一经查实，本站将立刻删除涉嫌侵权内容。