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sql复杂的子查询，横向合并结果集
第一个查询的结果集
select * from(select c.msName,a.msId,c.msPrice, c.msPrice*COUNT(a.msId) as totalMoney,sum(a.msAmount) as totalCount from BillConsume a right join (select top 1 msTime as startTime,GETDATE() as endTime from BillConsume where DateDiff(dd,msTime,getdate())=0 order by msTime asc) b on a.msTime between b.startTime and b.endTime and a.msId!=0left join Menus c on c.msId=a.msId group by a.msId ,c.msName,c.msPrice)s
连接两个结果集的语句
full join
第二个查询的结果集
(select sum(t.totalMoney) as allTotalMoney from ( select c.msName,a.msId,c.msPrice, c.msPrice*COUNT(a.msId) as totalMoney,sum(a.msAmount) as totalCount from BillConsume a right join (select top 1 msTime as startTime,GETDATE() as endTime from BillConsume where DateDiff(dd,msTime,getdate())=0 order by msTime asc) b on a.msTime between b.startTime and b.endTime and a.msId!=0left join Menus c on c.msId=a.msId group by a.msId ,c.msName,c.msPrice)t)t
连表的条件
on 1=1
sql复杂的子查询，横向合并结果集
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