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leetcode_024 Swap Nodes in Pairs

2024-09-22 22:57:37   213人阅读

Given a linked list, swap every two adjacent nodes and return its head.

For example,
Given 1->2->3->4, you should return the list as 2->1->4->3.

Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.

key:返回值出错，包括头结点

Python实现:

# Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution(object):
    def swapPairs(self, head):
        if head is None or head.next is None:
            return head
        dummy = ListNode(0)
        dummy.next = head
        p = dummy
        while p.next and p.next.next:
            tmp = p.next.next
            p.next.next = tmp.next
            tmp.next = p.next
            p.next = tmp
            p = p.next.next
        return dummy.next

 

leetcode_024 Swap Nodes in Pairs


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