1 #include<cstdio>
 2 #include<cstring>
 3 #include<ctime>
 4 #include<iostream>
 5 #define ll long long
 6 using namespace std;
 7 int mth[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
 8 ll solve(){
 9     int Y=0,M=0,D=0,h=0,m=0,s=0;
10     scanf("%d-%d-%d %d:%d:%d",&Y,&M,&D,&h,&m,&s);
11     Y-=2000;
12     ll ans=365*Y;
13     ans+=(Y+3)/4;// 处理闰年
　　　　// 比如2003年，Y-=2000  然后Y=3 (3+3)/4==1 即只有2000年一个闰年
14     for(int i=1;i<M;i++) ans+=mth[i];
15     ans+=(!(Y%4)&&M>2)?1:0;
16     ans+=D;
17     ans*=86400;
18     ans+=(h*60+m)*60+s;
19     return ans;
20 }
21 int main(){
22     freopen("two.in","r",stdin);
23     freopen("two.out","w",stdout);
24     ll s1=solve();
25     ll s2=solve();
26     printf("%I64d%s\n",s2-s1,s2-s1?"000":"");
27     return 0;
28 }