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android系统AES解密服务器加密数据错误解决方案
之前的做了一个外包项目，里边有一些敏感的信息需要AES加密，但是同样的代码在服务器就可以加密解密，在android系统中就解密失败，会出现pad block corrupted错误，下面给出解决方案， 亲测无问题！
AES.java
public class AES {
public static final String VIPARA = "0123456789abcdef";
public static final String bm = "UTF-8";
public static String encrypt(String dataPassword, String cleartext)
throws Exception {
IvParameterSpec zeroIv = new IvParameterSpec(VIPARA.getBytes());
SecretKeySpec key = new SecretKeySpec(dataPassword.getBytes(), "AES");
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.ENCRYPT_MODE, key, zeroIv);
byte[] encryptedData = http://www.mamicode.com/cipher.doFinal(cleartext.getBytes(bm));
return BASE64.encode(encryptedData);
}
public static String decrypt(String dataPassword, String encrypted)
throws Exception {
byte[] byteMi = BASE64.decode(encrypted);
IvParameterSpec zeroIv = new IvParameterSpec(VIPARA.getBytes());
SecretKeySpec key = new SecretKeySpec(dataPassword.getBytes(), "AES");
Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
cipher.init(Cipher.DECRYPT_MODE, key, zeroIv);
byte[] decryptedData = http://www.mamicode.com/cipher.doFinal(byteMi);
return new String(decryptedData,bm);
}
}
BASE64.java
public class BASE64 {
private static final char[] legalChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/".toCharArray();
/**
* data[]进行编码
* @param data
* @return
*/
public static String encode(byte[] data) {
int start = 0;
int len = data.length;
StringBuffer buf = new StringBuffer(data.length * 3 / 2);
int end = len - 3;
int i = start;
int n = 0;
while (i <= end) {
int d = ((((int) data[i]) & 0x0ff) << 16)
| ((((int) data[i + 1]) & 0x0ff) << 8)
| (((int) data[i + 2]) & 0x0ff);
buf.append(legalChars[(d >> 18) & 63]);
buf.append(legalChars[(d >> 12) & 63]);
buf.append(legalChars[(d >> 6) & 63]);
buf.append(legalChars[d & 63]);
i += 3;
if (n++ >= 14) {
n = 0;
buf.append(" ");
}
}
if (i == start + len - 2) {
int d = ((((int) data[i]) & 0x0ff) << 16)
| ((((int) data[i + 1]) & 255) << 8);
buf.append(legalChars[(d >> 18) & 63]);
buf.append(legalChars[(d >> 12) & 63]);
buf.append(legalChars[(d >> 6) & 63]);
buf.append("=");
} else if (i == start + len - 1) {
int d = (((int) data[i]) & 0x0ff) << 16;
buf.append(legalChars[(d >> 18) & 63]);
buf.append(legalChars[(d >> 12) & 63]);
buf.append("==");
}
return buf.toString();
}
private static int decode(char c) {
if (c >= ‘A‘ && c <= ‘Z‘)
return ((int) c) - 65;
else if (c >= ‘a‘ && c <= ‘z‘)
return ((int) c) - 97 + 26;
else if (c >= ‘0‘ && c <= ‘9‘)
return ((int) c) - 48 + 26 + 26;
else
switch (c) {
case ‘+‘:
return 62;
case ‘/‘:
return 63;
case ‘=‘:
return 0;
default:
throw new RuntimeException("unexpected code: " + c);
}
}
/**
* Decodes the given Base64 encoded String to a new byte array. The byte
* array holding the decoded data is returned.
*/
public static byte[] decode(String s) {
ByteArrayOutputStream bos = new ByteArrayOutputStream();
try {
decode(s, bos);
} catch (IOException e) {
throw new RuntimeException();
}
byte[] decodedBytes = bos.toByteArray();
try {
bos.close();
bos = null;
} catch (IOException ex) {
System.err.println("Error while decoding BASE64: " + ex.toString());
}
return decodedBytes;
}
private static void decode(String s, OutputStream os) throws IOException {
int i = 0;
int len = s.length();
while (true) {
while (i < len && s.charAt(i) <= ‘ ‘)
i++;
if (i == len)
break;
int tri = (decode(s.charAt(i)) << 18)
+ (decode(s.charAt(i + 1)) << 12)
+ (decode(s.charAt(i + 2)) << 6)
+ (decode(s.charAt(i + 3)));
os.write((tri >> 16) & 255);
if (s.charAt(i + 2) == ‘=‘)
break;
os.write((tri >> 8) & 255);
if (s.charAt(i + 3) == ‘=‘)
break;
os.write(tri & 255);
i += 4;
}
}
}