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【HDU1102】Constructing Roads(MST基础题)

最小生成树水题。prim一次AC

 

 1 #include <iostream> 2 #include <cstring> 3 #include <cstdlib> 4 #include <cstdio> 5 #include <cctype> 6 #include <cmath> 7 #include <algorithm> 8 #include <numeric> 9 10 #define typec int11 using namespace std;12 13 const int V = 105;14 const int inf = 0xffff;15 int vis[V]; typec lowc[V];16 int Map[105][105];17 18 typec prim (typec cost[][V], int n) {19     int i, j, p;20     typec minc, res = 0;21     memset(vis, 0, sizeof(vis));22     vis[0] = 1;23     for (i = 1; i < n; ++ i) lowc[i] = cost[0][i];24     for (i = 1; i < n; ++ i) {25         minc = inf; p = -1;26         for (j = 0; j < n; ++ j) {27             if (0 == vis[j] && minc > lowc[j]) {28                 minc = lowc[j]; p = j;29             }30         }31         if (inf == minc) return -1;32         res += minc; vis[p] = 1;33         for (j = 0; j < n; ++ j) {34             if (0 == vis[j] && lowc[j] > cost[p][j]) {35                 lowc[j] = cost[p][j];36             }37         }38     }39     return res;40 }41 42 int main () {43     //cout << inf <<endl;44     int n;45     while (cin >> n) {46         for (int i = 0 ; i < n; ++ i) {47             for (int j = 0 ; j < n; ++ j) {48                 scanf("%d", &Map[i][j]);49             }50         }51         int ok_line; cin >> ok_line;52         for (int i = 0; i < ok_line; ++ i) {53             int s, e;54             scanf("%d%d", &s, &e);55             Map[s - 1][e - 1] = Map[e - 1][s - 1] = 0;56         }57         cout << prim(Map, n) << endl;58     }59     return 0;60 }