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[leetcode]Gray Code

Gray Code

The gray code is a binary numeral system where two successive values differ in only one bit.

Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0.

For example, given n = 2, return [0,1,3,2]. Its gray code sequence is:

00 - 001 - 111 - 310 - 2

Note:
For a given n, a gray code sequence is not uniquely defined.

For example, [0,2,3,1] is also a valid gray code sequence according to the above definition.

For now, the judge is able to judge based on one instance of gray code sequence. Sorry about that.

这道题木有思路主要是因为不了解什么叫格雷码。

算法思路:

思路1:

格雷码公式法:gray = (binary) xor (binary >> 1)

代码

1 public class Solution {2     public List<Integer> grayCode(int n) {3         int size = 1 << n;4         List<Integer> list = new ArrayList<Integer>();5         for(int i = 0; i < size; list.add(i ^ i >> 1),i++);6         return list;7     }8 }

 

思路2:

不知道公式也没关系,只要弄明白格雷码的定义就好了,递归实现法也不难

代码如下:

 1 public class Solution { 2     public List<Integer> grayCode(int n) { 3         if(n == 0){ 4             List<Integer> list = new ArrayList<Integer>(); 5             list.add(0); 6             return list; 7         } 8         List<Integer> list = new ArrayList<Integer>(); 9         List<Integer> l = grayCode(n - 1); 10         list.addAll(l);11         for(int i = l.size() - 1; i >= 0 ;i--){12             list.add(l.get(i) +(1 << (n - 1)));13         }14         return list;15     }16 }