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杭电1020
Encoding
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 26063 Accepted Submission(s): 11467
Problem Description
Given a string containing only ‘A‘ - ‘Z‘, we could encode it using the following method:
1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, ‘1‘ should be ignored.
1. Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string.
2. If the length of the sub-string is 1, ‘1‘ should be ignored.
Input
The first line contains an integer N (1 <= N <= 100) which indicates the number of test cases. The next N lines contain N strings. Each string consists of only ‘A‘ - ‘Z‘ and the length is less than 10000.
Output
For each test case, output the encoded string in a line.
Sample Input
2ABCABBCCC
Sample Output
ABCA2B3C
Author
ZHANG Zheng
#include<stdio.h>
int main()
{
int n,m;
char c1,c2;
scanf("%d",&n);
c1=getchar();//此处为吸收换行符
while(n--)
{
int m=1;
c1=getchar();//此处吸收第一个字符
while(1)
{
c2=getchar();
if(c1!=c2)
{
if(m==1)
printf("%c",c1);
else
printf("%d%c",m,c1);
if(c2==‘\n‘)
break;
m=1; //此处重新化为1 重新计数
c1=c2;//将二复制给一 使能够循环进行吸收比较
}
else
m++;
}
printf("\n");
}
return 0;
}
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