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hdoj 1715 大菲波数 【字符串相加】

策略 :如题;

为什么昨天比赛的时候就没想出来,

模糊点 :

char c = a;

c += 1; //此时c = ‘b’;

注意:我是把最低位放到数组的较靠后的位置

AC by: SWS

 

链接http://acm.hdu.edu.cn/showproblem.php?pid=1715

代码:

#include<stdio.h>#include<string.h>char a[300], b[300], c[300];void f(int n){	strcpy(a, "1");	strcpy(b, "1");	int la, lb, i, j, k, s;	for(s = 3; s <= n; s ++){		la = strlen(a);		lb  = strlen(b);		i = j = k = 0;		while(i<la&&j<lb){			c[k++] = a[i]+b[j]-'0';			i++;			j++;		}		while(i<la){			c[k++] = a[i];			i++;		}		while(j<lb){			c[k++] = b[j];			j++;		}		i = 0;		while(i<k){			if(c[i]>'9'){				if(c[i+1] < '0')				c[i+1]= c[i+1]+1+'0';				else				c[i+1] += 1;				c[i] -= 10;			}			i++;		}		if(c[k]) c[k+1] = '\0';		else		c[k] = '\0';		strcpy(a, b);		strcpy(b, c);		memset(c, 0, sizeof(c));	}	lb = strlen(b);	for(i = lb-1; i >= 0; i --)	printf("%c", b[i]);	printf("\n");}int main(){	int t, n;	scanf("%d", &t);	while(t --){		scanf("%d", &n);		f(n);	}	return 0;}

AC time :2014 / 07 /31