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211. Add and Search Word - Data structure design
Design a data structure that supports the following two operations:
void addWord(word) bool search(word)
search(word) can search a literal word or a regular expression string containing only letters a-z
or .
. A .
means it can represent any one letter.
For example:
addWord("bad") addWord("dad") addWord("mad") search("pad") -> false search("bad") -> true search(".ad") -> true search("b..") -> true
Note:
You may assume that all words are consist of lowercase letters a-z
.
Use Tire
public class WordDictionary { class TrieNode { Map<Character, TrieNode> map; boolean isWord; public TrieNode(){ map = new HashMap<>(); isWord = false; } } private TrieNode root; public WordDictionary(){ root = new TrieNode(); } // Adds a word into the data structure. public void addWord(String word) { TrieNode node = root; for(char c : word.toCharArray()){ if(!node.map.containsKey(c)){ node.map.put(c, new TrieNode()); } node = node.map.get(c); } node.isWord = true; } // Returns if the word is in the data structure. A word could // contain the dot character ‘.‘ to represent any one letter. public boolean search(String word) { return dfs(word.toCharArray() , 0 , root); } public boolean dfs(char[] words, int deep , TrieNode root){ if(deep == words.length){ return root.isWord; } if(words[deep] == ‘.‘){ for(char s : root.map.keySet()){ if(dfs(words , deep+1 , root.map.get(s))) return true; } } else{ return root.map.containsKey(words[deep]) && dfs(words , deep+1 , root.map.get(words[deep])); } return false; } } // Your WordDictionary object will be instantiated and called as such: // WordDictionary wordDictionary = new WordDictionary(); // wordDictionary.addWord("word"); // wordDictionary.search("pattern");
211. Add and Search Word - Data structure design
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