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java按照集合中元素的属性进行排序示例代码
public class Student {
private String name;
private int age;
private int id;
public Student() {
super();
}
public Student(String name, int age, int id) {
super();
this.name = name;
this.age = age;
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
@Override
public String toString() {
return "id:"+id+"\tage"+age+"\tname"+name;
}
}
public class Test {
public static void main(String[] args) {
ArrayList<Student> list = new ArrayList<Student>();
list.add(new Student("张三",23,1));
list.add(new Student("张三",24,4));
list.add(new Student("李四",22,2));
list.add(new Student("王五",21,3));
Collections.sort(list,new Comparator<Student>() {
public int compare(Student s1, Student s2) {
if(!s1.getName().equals(s2.getName())){
return s2.getName().compareToIgnoreCase(s1.getName());
}
if(s1.getAge()>s2.getAge()){
return 1;// return 1代表需要交换位置
}
return -1;
}
});
for (int i = 0; i < list.size(); i++) {
System.out.println(list.get(i).toString());
}
}
}