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[JS Compose] 6. Semigroup examples

2024-08-27 09:31:21   219人阅读

Let‘s we want to combine two account accidently have the same name.

 

const acct1 = { name: ‘Nico‘, isPaid: true, points: 10, friends: [‘Franklin‘] }const acct2 = { name: ‘Nico‘, isPaid: false, points: 2, friends: [‘Gatsby‘] }

 

So, here we can use Semi-group to combine them, because the semi-group have the knowledge how to combine for each type of object.

So we change two accounts as:

const acct1 = { name: First(‘Nico‘), isPaid: All(true), points: Sum(10), friends: [‘Franklin‘] }const acct2 = { name: First(‘Nico‘), isPaid: All(false), points: Sum(2), friends: [‘Gatsby‘] }

 

But here we still have one problem which Object doesn‘t have ‘concat‘ method, so we need to use Immutable library to help:

Includes libarary:

const {Map} = Immutable;
const acct1 = Map({ name: First(‘Nico‘), isPaid: All(true), points: Sum(10), friends: [‘Franklin‘] })const acct2 = Map({ name: First(‘Nico‘), isPaid: All(false), points: Sum(2), friends: [‘Gatsby‘] })

 

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const {Map} = Immutable;const Sum = x =>({  x,  concat: ({x: y}) =>    Sum(x + y),  inspect: () =>    `Sum(${x})`})const All = x =>({  x,  concat: ({x: y}) =>    All(x && y),  inspect: () =>    `All(${x})`})const First = x =>({  x,  concat: _ =>    First(x),  inspect: () =>    `First(${x})`})const acct1 = Map({ name: First(‘Nico‘), isPaid: All(true), points: Sum(10), friends: [‘Franklin‘] })const acct2 = Map({ name: First(‘Nico‘), isPaid: All(false), points: Sum(2), friends: [‘Gatsby‘] })const res = acct1.concat(acct2)// Showing resultsconsole.log("Friend 1: ", res.toJS().friends[0]) //Friend 1: Franklinconsole.log("Friend 2: ", res.toJS().friends[1]) //Friend 2: Gatsbyconsole.log("isPaid: ", res.toJS().isPaid.x) //isPaid: falseconsole.log("Name: ", res.toJS().name.x) // Name: Nicoconsole.log("Points: ", res.toJS().points.x) // Points: 12

 

[JS Compose] 6. Semigroup examples


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