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HDU 4267 A Simple Problem with Integers

2024-08-12 15:30:26   220人阅读

A Simple Problem with Integers

Time Limit: 5000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5339    Accepted Submission(s): 1693


Problem Description
Let A1, A2, ... , AN be N elements. You need to deal with two kinds of operations. One type of operation is to add a given number to a few numbers in a given interval. The other is to query the value of some element.
 

 

Input
There are a lot of test cases. 
The first line contains an integer N. (1 <= N <= 50000)
The second line contains N numbers which are the initial values of A1, A2, ... , AN. (-10,000,000 <= the initial value of Ai <= 10,000,000)
The third line contains an integer Q. (1 <= Q <= 50000)
Each of the following Q lines represents an operation.
"1 a b k c" means adding c to each of Ai which satisfies a <= i <= b and (i - a) % k == 0. (1 <= a <= b <= N, 1 <= k <= 10, -1,000 <= c <= 1,000)
"2 a" means querying the value of Aa. (1 <= a <= N)
 

 

Output
For each test case, output several lines to answer all query operations.
 

 

Sample Input
4
1 1 1 1
14
2 1
2 2
2 3
2 4
1 2 3 1 2
2 1
2 2
2 3
2 4
1 1 4 2 1
2 1
2 2
2 3
2 4
 

 

Sample Output
1
1
1
1
1
3
3
1
2
3
4
1
 

 

Source
2012 ACM/ICPC Asia Regional Changchun Online
 
 
 
解析：55个树状数组。
 
 
 
#include <cstdio>#include <cstring>#define lowbit(x) (x)&(-x)const int MAXN = 50000+5;int num[MAXN];int c[MAXN][11][11];int n;void add(int x, int k, int mod, int val){    for(int i = x; i <= n; i += lowbit(i))        c[i][k][mod] += val;}int sum(int x, int a){    int ret = 0;    for(int i = x; i > 0; i -= lowbit(i))        for(int j = 1; j <= 10; ++j)            ret += c[i][j][a%j];    return ret;}int main(){    while(~scanf("%d", &n)){        for(int i = 1; i <= n; ++i)            scanf("%d", &num[i]);        memset(c, 0, sizeof(c));        int q, a, b, k, c, op;        scanf("%d", &q);        while(q--){            scanf("%d", &op);            if(op == 1){                scanf("%d%d%d%d", &a, &b, &k, &c);                add(a, k, a%k, c);                add(b+1, k, a%k, -c);            }            else{                scanf("%d", &a);                printf("%d\n", num[a]+sum(a, a));            }        }    }    return 0;}

　　

HDU 4267 A Simple Problem with Integers


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