题目大意:关于网络阻塞命令延迟的处理。命令就分为三种对栈的处理。但是如果接收到一个操作,它后面的操作都要先取消不做,再做这个操作,再做之前取消了的操
https://www.u72.net/daima/0en3.html - 2024-07-18 14:44:23 - 代码库LightningTime Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1457 Accepted Submissio
https://www.u72.net/daima/0eh4.html - 2024-07-18 14:48:30 - 代码库同上,区间更新,单点查询。#include<cstdio>#include<cstring>#include<cmath>#include<iostream>#include<algorithm>#include<set>#include<map>
https://www.u72.net/daima/09xz.html - 2024-07-18 14:15:59 - 代码库~~~NotOnlySuccess 出的题~~~看了题之后觉得和HDU 4027有点像,给的K很小,只有10,目测只要有人升级的时候直接更新到叶子节点就ok了。不过不同于HDU 4027 的是,那
https://www.u72.net/daima/1krs.html - 2024-07-18 20:20:00 - 代码库题目描述 Description有n个数和5种操作add a b c:把区间[a,b]内的所有数都增加cset a b c:把区间[a,b]内的所有数都设为csum a b:查询区间[a,b]的区
https://www.u72.net/daima/5rmr.html - 2024-09-06 13:41:51 - 代码库Just a HookTime Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 30080 Accepted Submi
https://www.u72.net/daima/5r8v.html - 2024-09-06 13:31:51 - 代码库Minimum Inversion Number DescriptionThe inversion number of a given number se
https://www.u72.net/daima/7w7n.html - 2024-07-25 11:17:21 - 代码库都是些简单的东西,所以直接上代码了。/** * Created by huangjacky on 14-10-3. */function Node(element, left, right) { this.element = element;
https://www.u72.net/daima/7x49.html - 2024-07-25 12:17:34 - 代码库Relief grainTime Limit: 10000/5000 MS (Java/Others) Memory Limit: 100000/100000 K (Java/Others)Total Submission(s): 861 Accepted Subm
https://www.u72.net/daima/73xk.html - 2024-07-25 15:53:42 - 代码库题目链接:hdu 2871 Memory Control题目大意:模拟一个内存分配机制。Reset:重置,释放全部空间New x:申请内存为x的空间,输出左地址Free x:释放地址x所在的内存
https://www.u72.net/daima/7386.html - 2024-07-25 16:14:06 - 代码库★★ 输入文件:trie.in 输出文件:trie.out 简单对比 时间限制:1 s 内存限制:128 MB在进行文法分析的时候,通常需要检测一个单词是否在我们的单词列
https://www.u72.net/daima/709z.html - 2024-09-10 08:32:57 - 代码库点击打开链接题目链接敌兵布阵Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 45253
https://www.u72.net/daima/52k0.html - 2024-07-23 12:24:11 - 代码库题目链接 :http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5332比赛的时候没有做出来,赛后看了官方题解,虽然各种orz但是依旧只能orz(标程
https://www.u72.net/daima/7wbs.html - 2024-07-25 10:46:20 - 代码库题目链接:hdu 1540 Tunnel Warfare题目大意:有连续的N个城镇,三种操作:D x:第x城镇被破坏Q x:插叙第x城镇所在联通块有多少个城镇没有被破坏R:修复最后一个被
https://www.u72.net/daima/7wb8.html - 2024-07-25 10:47:33 - 代码库题目链接:hdu 2871 Memory Control题目大意:模拟一个内存分配机制。Reset:重置,释放所有空间New x:申请内存为x的空间,输出左地址Free x:释放地址x所在的内存
https://www.u72.net/daima/7rrh.html - 2024-07-25 07:11:26 - 代码库题目链接:zoj 3813 Alternating Sum题目大意:给定一个P,S是以P为循环的无限串,定义G(i,j),现在有两种操作:1 x d;将P中x的位置变为d2 l r:查询S中l-r之间所有的
https://www.u72.net/daima/4n2u.html - 2024-07-21 21:35:47 - 代码库一开始没有思路,之后问了一下学长,需要逆向处理输入。最后一个加入队列的肯定是没有冲突的,所以我们可以从最后一个开始处理,从后往前,找第 i &#43; 1个空着
https://www.u72.net/daima/44ba.html - 2024-07-22 13:42:06 - 代码库using System;using System.Collections.Generic;using System.Linq;using System.Reflection;using System.Text;using System.Threading.Tasks;using
https://www.u72.net/daima/6r83.html - 2024-07-24 06:30:36 - 代码库题目链接:http://poj.org/problem?id=2528Time Limit: 1000MS Memory Limit: 65536KTotal Submissions: 43201 Accepted: 12591DescriptionThe citizens
https://www.u72.net/daima/6c07.html - 2024-07-24 05:21:46 - 代码库1 #include<stdio.h> 2 #include<iostream> 3 4 using namespace std; 5 struct TreeNode 6 { 7 int data; 8 TreeNode *Le
https://www.u72.net/daima/6dzw.html - 2024-09-07 23:14:05 - 代码库