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Problem DescriptionEarth Hour is an annual international event created by the WWF (World Wide Fund for Nature/World Wildlife Fund), held on
https://www.u72.net/daima/xn71.html - 2024-07-16 18:41:54 - 代码库Dijkstra算法：首先，引进一个辅助向量D，它的每个分量D[i]表示当前所找到的从始点v到每个终点vi的的长度：如D[3]=2表示从始点v到终点3的路径相对最小长度为2
https://www.u72.net/daima/rknb.html - 2024-07-11 18:40:21 - 代码库题目地址：HDU 3832这个题的这个方法我无法给出证明。我当时这个灵感出来的时候是想的是要想覆盖的点最少，那就要尽量重复利用这些点，然后要有两个之间是通
https://www.u72.net/daima/v0ku.html - 2024-07-15 07:01:17 - 代码库B. Jzzhu and CitiesJzzhu is the president of country A. There are n cities numbered from 1 to n in his country. City 1 is the capital of A.
https://www.u72.net/daima/v39r.html - 2024-07-15 10:20:42 - 代码库题意：给你n（最多150）个点的坐标，给出邻接矩阵，并且整个图至少两个联通块，现在让你连接一条边，使得所有可联通的两点的最短距离的最大值最小。题解：先dfs染色，再
https://www.u72.net/daima/sb5h.html - 2024-08-20 03:12:20 - 代码库Computer NetTime limit: 2.0 secondMemory limit: 64 MBBackgroundComputer net is created by consecutive computer plug-up to one that ha
https://www.u72.net/daima/c80h.html - 2024-08-18 02:50:20 - 代码库看了这些代码之后 总结了一下 其实就那三个for 循环 一：找与v有连接的点 。二：从这些连接的点找到最小，把他看成是下一次的v 。 三： 你要把有出现的那些
https://www.u72.net/daima/vfaz.html - 2024-07-14 23:44:32 - 代码库题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=2112题目大意：给出起点和终点，然后算出最短的路。不过有好多细节要注意：(1)起始点和终止点相等的时
https://www.u72.net/daima/x6zu.html - 2024-07-17 11:46:48 - 代码库TravelTime Limit: 10000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2789 Accepted Submission
https://www.u72.net/daima/1kca.html - 2024-08-30 04:40:39 - 代码库1321: CX and girlsTime Limit: 1 Sec Memory Limit: 128 MBSubmit: 432 Solved: 124[Submit][Status][Web Board]Description CX是要赶去上课，为
https://www.u72.net/daima/336v.html - 2024-07-21 12:13:49 - 代码库Invitation CardsTime Limit: 8000MS Memory Limit: 262144KTotal Submissions: 19215 Accepted: 6311DescriptionIn the age of television, not many
https://www.u72.net/daima/0a7k.html - 2024-07-17 17:35:43 - 代码库题目链接：http://poj.org/problem?id=2253FroggerTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 25773 Accepted: 8374DescriptionFreddy
https://www.u72.net/daima/03r7.html - 2024-07-18 08:53:03 - 代码库WuKongTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1800 Accepted Submission(
https://www.u72.net/daima/2b9u.html - 2024-09-01 01:13:04 - 代码库http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1742Problem ?Lift HoppingTime Limit: 1 seco
https://www.u72.net/daima/3ds8.html - 2024-07-21 00:00:06 - 代码库RoadblocksTime Limit: 2000MS Memory Limit: 65536KTotal Submissions: 7149 Accepted: 2663DescriptionBessie has moved to a small farm and somet
https://www.u72.net/daima/u448.html - 2024-07-14 10:59:12 - 代码库只想说 字典树必释放内存#include <cstdio>#include <cstring>#include <algorithm>using namespace std;struct node { node *next[53]; i
https://www.u72.net/daima/124r.html - 2024-07-19 08:57:39 - 代码库#include <bits/stdc++.h>#include <ext/hash_map>#include <ext/hash_set>#include <ext/pb_ds/assoc_container.hpp>#include <ext/pb_ds/priority_q
https://www.u72.net/daima/2hkh.html - 2024-07-19 20:43:46 - 代码库http://poj.org/problem?id=3255同匈牙利游戏。但是我发现了一个致命bug。就是在匈牙利那篇，应该dis2单独if，而不是else if，因为dis2和dis1相对独立。有可
https://www.u72.net/daima/2aff.html - 2024-07-19 18:03:12 - 代码库Earth HourTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 125536/65536 K (Java/Others)Total Submission(s): 1518 Accepted Submiss
https://www.u72.net/daima/xc2a.html - 2024-07-17 00:56:39 - 代码库ArbitrageTime Limit: 1000MS Memory Limit: 65536KTotal Submissions: 15640 Accepted: 6563DescriptionArbitrage is the use of discrepancies in c
https://www.u72.net/daima/xwe2.html - 2024-07-17 05:32:36 - 代码库