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今日已更新 22 篇代码解决方案
Algorithm.( Augmenting Path Algorithm )Input: An X-Y bigraph G, a matching M in G, and the set U of M-unsaturated vertices in X.
https://www.u72.net/daima/c7a3.html - 2024-07-11 10:36:27 - 代码库二分图设G=(V,E)是一个无向图，如果顶点V可分割为两个互不相交的子集(A,B)，并且图中的每条边（i，j）所关联的两个顶点i和j分别属于这两个不同的顶点集(i in A,
https://www.u72.net/daima/r15w.html - 2024-08-19 01:37:23 - 代码库The Perfect StallTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 19174 Accepted: 8696DescriptionFarmer John
https://www.u72.net/daima/m4z5.html - 2024-09-17 10:41:42 - 代码库Algorithm.( Augmenting Path Algorithm )Input: An X-Y bigraph G, a matching M in G, and the set U of M-unsaturated verti
https://www.u72.net/daima/ere4.html - 2024-09-15 03:10:08 - 代码库The Perfect StallTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 19174 Accepted: 8696DescriptionFarmer John completed his new barn
https://www.u72.net/daima/nc4wn.html - 2024-08-08 13:47:05 - 代码库KM算法 1 #include <bits/stdc++.h> 2 #define N 1500 3 #define inf 999999999 4 using namespace std; 5 int a[N],bs[N],nx=0,ny=0,k; 6 in
https://www.u72.net/daima/16bw.html - 2024-08-31 06:12:25 - 代码库二分图：顶点可以分类两个集合X和Y，所有的边关联的两个顶点恰好一个属于集合X，另一个属于集合Y.二分图匹配：给定一个二分图G，在G的一个子图M中，M的边集中的任
https://www.u72.net/daima/768x.html - 2024-07-25 18:55:38 - 代码库Machine ScheduleTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 11922 Accepted: 5077DescriptionAs we all know, machine schedu
https://www.u72.net/daima/5z01.html - 2024-07-22 22:55:29 - 代码库#include <iostream>#include <cstdio>#include <memory.h>using namespace std;int n,m,num,temp,sum;int re[201][201],link[201];//牛与牛栏的对应
https://www.u72.net/daima/8szz.html - 2024-07-26 08:43:25 - 代码库一般情况下，我们用的都是简单图。带权图，无向图；还有各种算法，像Floyd，SPFA，Dijkstra……但是，在我们需要进行一些匹配问题的时候，我们就不能够只是用简单图了
https://www.u72.net/daima/ec8m.html - 2024-09-15 01:30:23 - 代码库传送门 题意：给一个N*N的矩阵，有些格子有障碍，要求我们消除这些障碍，问每次消除一行或一列的障碍，最少要几次。 解析：把每一行与每一列当做二分图两边的点。
https://www.u72.net/daima/nnzes.html - 2024-09-19 21:07:29 - 代码库Girls and BoysTime Limit: 5000MS Memory Limit: 10000KTotal Submissions: 10912 Accepted: 4887DescriptionIn the second
https://www.u72.net/daima/nbmn5.html - 2024-10-05 15:06:02 - 代码库886. [USACO 4.2] 完美的牛栏★★☆ 输入文件：stall4.in 输出文件：stall4.out 简单对比时间限制：1 s 内存限制：128 MB USACO/stall4(译by Fel
https://www.u72.net/daima/s50c.html - 2024-08-21 00:09:17 - 代码库Girls and BoysTime Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7044 Accepted Su
https://www.u72.net/daima/smw2.html - 2024-07-13 16:42:08 - 代码库1433: [ZJOI2009]假期的宿舍Time Limit: 10 Sec Memory Limit: 162 MBSubmit: 2544 Solved: 1074[Submit][Status][Discuss]DescriptionInputOutpu
https://www.u72.net/daima/33en.html - 2024-09-03 12:12:31 - 代码库I‘m Telling the TruthTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1482 Accep
https://www.u72.net/daima/9k2f.html - 2024-07-27 05:12:57 - 代码库过山车Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11509 Accepted Submission(
https://www.u72.net/daima/nazm6.html - 2024-07-30 07:15:33 - 代码库过山车Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 22693 Accepted Submission(
https://www.u72.net/daima/nv8zx.html - 2024-11-02 09:25:39 - 代码库题目大意：学生给出其成绩区间，但可能出现矛盾情况，找出合理组合使没有说谎的人尽可能多，并按maximum lexicographic规则输出组合。//用学生去和成绩匹配，成
https://www.u72.net/daima/1x3.html - 2024-08-11 00:20:05 - 代码库一、骆驼命名法： 小驼峰法（camel方法）变量一般用小驼峰法标识。 第一个单词以小写字母开始；第二个单词的首字母大写或每一个单词的首字母都采用大
https://www.u72.net/daima/fs1x.html - 2024-08-16 20:27:05 - 代码库