关于异步电动机(33)代码解决方案的搜索结果

#include <stdio.h> //s为初态，z为终态 int in(int s,int z){ if(s == z) { printf("\n这个状态属于 Z"); return 1;

https://www.u72.net/daima/um10.html - 2024-08-23 02:10:55 - 代码库

#include <stdio.h> //s为初态，z为终态int in(int s,int z){ if(s == z) { printf("3\nlook!the last status belon

https://www.u72.net/daima/vza5.html - 2024-08-23 05:50:38 - 代码库

#include<string.h>#include<stdio.h>#include<stdlib.h>int main(){ char p[30][30]; char q[30][30]; int line=0; int n;

https://www.u72.net/daima/vzn8.html - 2024-08-23 05:54:45 - 代码库

#include<stdio.h>#define MAX 20main(){ int i=0,j=0,k,l,m,n,number; char ch; char a[MAX][MAX]; printf("请输入正规式：");

https://www.u72.net/daima/x248.html - 2024-08-27 15:20:13 - 代码库

#include<stdio.h>#define N 30char str[N]={NULL};int st[N];int t=0,k=0,a,t1=0;struct node//定义一个队列{ char data; struct nod

https://www.u72.net/daima/x64s.html - 2024-08-27 21:24:58 - 代码库

BZOJ3998#include <cstdio>#include <cstring>using namespace std; int last,dis[1000011],fa[1000011],a[1000011][26],cnt,sum[1000011];

https://www.u72.net/daima/3zh5.html - 2024-09-02 10:45:16 - 代码库

#include<stdio.h>main(){ int i=0,j=0,x=0,y; int number=2; int count=0; char ch; char a[100][100]; printf("请输入

https://www.u72.net/daima/xvah.html - 2024-08-27 06:46:12 - 代码库

解决字符串问题 1 #include <stdio.h> 2 #include <algorithm> 3 #include <iostream> 4 #include <string.h> 5 #include <queue> 6 using name

https://www.u72.net/daima/nz8vn.html - 2024-09-22 22:44:37 - 代码库

#include<cstdio>#include<cstring>#include<iostream>#include<algorithm>#define L 51#define LL 100000002using namespace std;char c[11]

https://www.u72.net/daima/nsvws.html - 2024-10-17 15:19:01 - 代码库