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1.以oracle用户登录oracle数据库，执行如下命令登录数据库：sqlplus / as sysdba2.运行如下命令：@?/rdbms/admin/awrrpt.sql3.出现如下信息时，直接回车（默认HT
https://www.u72.net/daima/b5x6.html - 2024-07-09 08:21:21 - 代码库Roman to IntegerGiven a roman numeral, convert it to an integer.Input is guaranteed to be within the range from 1 to 3999.SOLUTION 1:思路
https://www.u72.net/daima/nkr89.html - 2024-08-03 23:04:11 - 代码库【题目】Given a binary tree and a sum, find all root-to-leaf paths where each path‘s sum equals the given sum.For example:Given the below b
https://www.u72.net/daima/nkrse.html - 2024-08-03 22:37:54 - 代码库1031_Campus题目链接：http://soj.me/1031 题目大意：给出四个校区的一些地点之间的距离，地点名用字符串来表示，问某两个地点之间的最短路径长度，典型的单源最
https://www.u72.net/daima/nk8cm.html - 2024-08-04 11:50:17 - 代码库题目来源：A Mountaineer （不知道该链接是否可以直接访问，所以将题目复制下来了）题目如下：D - A MountaineerTime limit : 2sec / Stack limit : 256MB / Mem
https://www.u72.net/daima/nawhb.html - 2024-07-30 17:04:19 - 代码库网络流刷的第一题，从早上8:00的通识课开始想这题。最终在晚上才AC了……网络流好难 1 /* 2 Run ID User Problem Result Me
https://www.u72.net/daima/nhekz.html - 2024-08-03 11:53:56 - 代码库1321_Robot题目链接：http://soj.me/1321 题目大意：给一个矩阵，每一个点上面的数字表示走到该点需要的花费，找出给定起点到终点的最小总花费 思路：每个格子看
https://www.u72.net/daima/nhed6.html - 2024-08-03 11:57:25 - 代码库【问题描述】音乐组同事反馈了一个必现Native Crash问题，tombstone如下：pid: 5028, tid: 5028, name: com.miui.player >>> com.miui.player <<<sig
https://www.u72.net/daima/nzca4.html - 2024-09-21 22:57:32 - 代码库【NE现场】pid: 6715, tid: 6719, name: Signal Catcher >>> com.android.contacts <<<signal 11 (SIGSEGV), code 1 (SEGV_MAPERR), fault addr 0x
https://www.u72.net/daima/nzk68.html - 2024-09-21 17:57:42 - 代码库Longest Valid ParenthesesGiven a string containing just the characters ‘(‘ and ‘)‘, find the length of the longest valid (well-formed)
https://www.u72.net/daima/nkz37.html - 2024-08-03 16:19:02 - 代码库【题目】Given an array S of n integers, are there elements a, b, c, and d in S such that a &#43; b &#43; c &#43; d = target? Find all unique
https://www.u72.net/daima/nadbd.html - 2024-07-30 09:23:30 - 代码库DescriptionGiven a 2D grid, each cell is either a wall 2, a zombie 1 or people 0 (the number zero, one, two).Zombies can turn the nearest p
https://www.u72.net/daima/nzrh5.html - 2024-09-22 00:41:35 - 代码库百度搜索：小强测试品牌挨踢脱口秀，将技术娱乐化，碎片系统化，尽在荔枝FM交流群：138269539以下内容节选自《小强软件测试疯狂讲义-性能及自动化》一书如果对你
https://www.u72.net/daima/nhd74.html - 2024-09-23 12:54:19 - 代码库敌兵布阵Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 46897 Accepted Submissio
https://www.u72.net/daima/nduv8.html - 2024-08-05 01:57:15 - 代码库【题目】Given a string s, partition s such that every substring of the partition is a palindrome.Return the minimum cuts needed for a palind
https://www.u72.net/daima/nhzf1.html - 2024-08-02 10:48:11 - 代码库Longest Common Prefix Total Accepted: 24665 Total Submissions: 92370My SubmissionsQuestion Solution Write a function to find the longest co
https://www.u72.net/daima/nhu0d.html - 2024-08-02 23:13:20 - 代码库这道题的难点应该就是想到这是一道二分图匹配想到这点以后，就是建图了//by baobaopangzi88#include <iostream>#include <sstream>#include <ios>#inclu
https://www.u72.net/daima/ndffr.html - 2024-08-04 21:55:27 - 代码库第一批90后开始承担起家庭的责任，开始成为社会的主要力量的时候，另一批新势力渐渐的萌芽，那就是95后。95后的年轻人有着伴随智能设备成长的经历，只能设
https://www.u72.net/daima/nfxvh.html - 2024-08-07 08:30:47 - 代码库Pow(x, n) Implement pow(x, n).SOLUTION 1:使用二分法。1. 负数的情况，使用以下的公式转化为求正数power，另外，考虑到MIN_VALUE可能会造成越界的情况，我们
https://www.u72.net/daima/nrzsn.html - 2024-08-08 23:31:15 - 代码库项目评估是指在项目可行性研究的基础上，由第三方（国家、银行或有关机构）根据国家颁布的政策、法规、方法、参数和条例等，从项目（或企业）、国民经济、社会的角
https://www.u72.net/daima/nrnwf.html - 2024-10-12 19:36:02 - 代码库