Description 在无向图中,如果从顶点vi到顶点vj有路径,则称vi和vj连通。如果图中任意两个顶点之间都连通,则称该图为连通图,否则,称该图为非连通图,则其中的极
https://www.u72.net/daima/11hb.html - 2024-07-19 07:24:48 - 代码库在无向图中,如果从顶点vi到顶点vj有路径,则称vi和vj连通。如果图中任意两个顶点之间都连通,则称该图为连通图,否则,称该图为非连通图,则其中的极大连通子图
https://www.u72.net/daima/1e8d.html - 2024-07-19 16:48:27 - 代码库坑,没找到模板题。暂时先放一放。有两种版本的,不知道那个比较好。http://blog.csdn.net/u013497977/article/details/47188489http://blog.csdn.net
https://www.u72.net/daima/mzbd.html - 2024-09-16 08:40:36 - 代码库求割点个数/* gyt Live up to every day */#include<cstdio>#include<cmath>#include<iostream>#include<algorithm>#i
https://www.u72.net/daima/nvbhu.html - 2024-10-29 02:16:39 - 代码库感觉挺有趣的,就谢了已发,其实就是判断这个有向图是否两两连通。。。。。解释就是这个博客上的tarjan算法我实现后代码如下。。。#include <stdio.h>#i
https://www.u72.net/daima/nbk7w.html - 2024-08-05 21:15:19 - 代码库[有向图强连<em>通分</em>量]在有向图G中,如果两个顶点间至少存在一条路径,称两个顶点强连通(strongly connected)。
https://www.u72.net/daima/mfzw.html - 2024-09-16 16:06:28 - 代码库之前Tarjan算法求强连<em>通分</em>量博文中,代码实现用到了固定大小数组,扩展起来&#20284;乎并不是很方便,在java里这样来实现本身就是不太妥当的,所以下面给出一个
https://www.u72.net/daima/59re.html - 2024-07-23 19:08:56 - 代码库点击打开链接无向图的双连<em>通分</em>量#include<cstdio>#include<stack>#include<vector
https://www.u72.net/daima/5v9u.html - 2024-07-23 08:33:19 - 代码库有向图,不经过重复点的最长链,强连<em>通分</em>量大小不超过5。每个强连<em>通分</em>量内部暴力预处理任意两对点之间的最长路,外面DAG上dp。不是很好写,但是预处理完了之
https://www.u72.net/daima/nvfnf.html - 2024-10-29 07:52:01 - 代码库还是贴一份tarjan的代码吧 ,QwQ 1 #include <algorithm> 2 #include <iostream> 3 #include <cstdlib> 4 #include <cstring> 6 #include <cstdio>
https://www.u72.net/daima/b2n3.html - 2024-08-16 04:41:41 - 代码库by:白书#define M 10000int pre[M],dfs_clock,iscut[M],low[M],bcc_cnt,bccno[M];vector<int>G[M],bcc[M];struct Edge{ int u,v; Edge(int from
https://www.u72.net/daima/ccvv.html - 2024-07-10 22:29:40 - 代码库有重边的话重边就不被包含在双连通里了#include <cstdio>#include <vector >using namespace std;const int maxn=1001;vector<int >G[maxn];int low[m
https://www.u72.net/daima/0rbh.html - 2024-07-18 00:58:24 - 代码库链接:http://poj.org/problem?id=1236代码:31 int index = 0;32 int low[MAXN], dfn[MAXN];33 int vis[MAXN], bel[MAXN];34 VI G[MAXN];35 stac
https://www.u72.net/daima/msb8.html - 2024-09-16 21:01:53 - 代码库1 #include <algorithm> 2 #include <cstdio> 3 4 using namespace std; 5 6 const int N(100015); 7 int n,m,v,u; 8 int edgesum,head[N]; 9 10 s
https://www.u72.net/daima/nnrh2.html - 2024-09-20 06:46:55 - 代码库来,水水模板吧。。。。。#include<cstdio>#include<cstring>#include<cstdlib>#include<iostream>#include<algorithm>#define N 10000using namespace
https://www.u72.net/daima/nfvfz.html - 2024-10-07 07:04:02 - 代码库割顶:对于无向图G,如果删除某个点u后,连<em>通分</em>量的数目增加, 称u为图的割顶。对于连通图,割顶就是删除之后使图不再连通的点。 割顶的求解依如下定理: 在
https://www.u72.net/daima/40kd.html - 2024-09-04 23:44:40 - 代码库所以缩点,若出度为零的点(强联<em>通分</em>量)唯一,则
https://www.u72.net/daima/3mfz.html - 2024-07-21 19:15:50 - 代码库先上代码:#include <iostream>#include <cstring>#include <vector>#include <stack>using namespace std;int G[1000][1000];int pre[1000],sccno[1000
https://www.u72.net/daima/uufb.html - 2024-07-14 03:35:17 - 代码库NetworkTime Limit: 5000MS Memory Limit: 65536KTotal Submissions: 9434 Accepted: 3511DescriptionA network administrator ma
https://www.u72.net/daima/weeu.html - 2024-08-26 10:51:52 - 代码库Caocao‘s BridgesTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1499 Accepted S
https://www.u72.net/daima/315z.html - 2024-07-21 10:16:51 - 代码库