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【Leetcode长征系列】Single Number II
原题:
Given an array of integers, every element appears three times except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution { public: int singleNumber(int A[], int n) { int bitnum[32] = {0}; int res = 0; for (int i = 0; i<32; i++){ for (int j = 0; j<n; j++) bitnum[i] += (A[j]>>i)&1; res |= (bitnum[i]%3)<<i; } return res; } };我本觉得
res |= (bitnum[i]%3)<<i;可以用
res =res+ (bitnum[i]%3)<<i;代替,
或者是
bitnum[i] += (A[j]>>i)&1;可以用
bitnum[i] = bitnum[i]+ (A[j]>>i)&1;代替
不过全部报错
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