首页 > 代码库 > hdu4734(数位DP)

hdu4734(数位DP)

F(x)

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1684    Accepted Submission(s): 650


Problem Description
For a decimal number x with n digits (AnAn-1An-2 ... A2A1), we define its weight as F(x) = An * 2n-1 + An-1 * 2n-2 + ... + A2 * 2 + A1 * 1. Now you are given two numbers A and B, please calculate how many numbers are there between 0 and B, inclusive, whose weight is no more than F(A).
 

Input
The first line has a number T (T <= 10000) , indicating the number of test cases.
For each test case, there are two numbers A and B (0 <= A,B < 109)
 

Output
For every case,you should output "Case #t: " at first, without quotes. The t is the case number starting from 1. Then output the answer.
 

Sample Input
3 0 100 1 10 5 100
 

Sample Output
Case #1: 1 Case #2: 2 Case #3: 13

题意:RT

思路:dp[i][j]表示从最低位到第i位取得的总和 <= j 的方案数,当然在递归的过程中还要判断是否为边界,为边界就不能记忆化了,所以不为边界的时候就可以记录dp值

<script src="https://code.csdn.net/snippets/460473.js" type="text/javascript"></script>

hdu4734(数位DP)