首页 > 代码库 > ACdream1187(简单找规律)
ACdream1187(简单找规律)
C - Problem C
Time Limit: 2000/1000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others)
SubmitStatus
Problem Description
Consider an infinite complete binary tree where the root node is 1/1 and left and right childs of node p/q are p/(p+q) and (p+q)/q, respectively. This tree looks like:
1/1 ______|______ | | 1/2 2/1 ___|___ ___|___ | | | | 1/3 3/2 2/3 3/1 ...
It is known that every positive rational number appears exactly once in this tree. A level-order traversal of the tree results in the following array:
1/1, 1/2, 2/1, 1/3, 3/2, 2/3, 3/1, ...
Please solve the following two questions:
- Find the n-th element of the array, where n starts from 1. For example, for the input 2, the correct output is 1/2.
- Given p/q, find its position in the array. As an example, the input 1/2 results in the output 2.
Input
The first line of the input gives the number of test cases, T(1 ≤ T ≤ 100).
T test cases follow. Each test case consists of one line.
The line contains a problem id (1 or 2) and one or two additional integers:
- If the problem id is 1, then only one integer n is given, and you are expected to find the n-th element of the array.
- If the problem id is 2, then two integers p and q are given, and you are expected to find the position of p/q in the array.
p and q are relatively prime.
1 ≤ n, p, q ≤ 264-1
p/q is an element in a tree with level number ≤ 64.
Output
For each test case:
- If the problem id is 1, then output one line containing "Case #x: p q", where x is the case number (starting from 1), and p, q are numerator and denominator of the asked array element, respectively.
- If the problem id is 2, then output one line containing "Case #x: n", where x is the case number (starting from 1), and n is the position of the given number.
Sample Input
4 1 2 2 1 2 1 5 2 3 2
Sample Output
Case #1: 1 2 Case #2: 2 Case #3: 3 2 Case #4: 5
题意:RT
思路:规律很明显,递归往上求解即可,这题要用unsigned long long,结果我比赛的时候用long long,被这个坑到了,深刻的记下了
<script src="https://code.csdn.net/snippets/460740.js" type="text/javascript"></script>
ACdream1187(简单找规律)
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。