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Binary Tree Preorder Traversal
Given a binary tree, return the preorder traversal of its nodes‘ values.
For example:
Given binary tree {1,#,2,3},
1 2 / 3
return [1,2,3].
Note: Recursive solution is trivial, could you do it iteratively?
1 /** 2 * Definition for binary tree 3 * struct TreeNode { 4 * int val; 5 * TreeNode *left; 6 * TreeNode *right; 7 * TreeNode(int x) : val(x), left(NULL), right(NULL) {} 8 * }; 9 */10 class Solution {11 public:12 vector<int> preorderTraversal(TreeNode *root) {13 14 vector<int> vec;15 getVal(vec, root);16 return vec;17 }18 19 void getVal(vector<int> &vec, TreeNode *root){20 21 if(root != NULL){22 vec.push_back(root->val);23 getVal(vec, root->left);24 getVal(vec, root->right);25 }26 }27 };
Binary Tree Preorder Traversal
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