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ZigZag-LeetCode
题目:
The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H NA P L S I I GY I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string text, int nRows);
convert("PAYPALISHIRING", 3)
should return "PAHNAPLSIIGYIR"
.
Zigzag:即循环对角结构.
向下循环:nRows
斜角线循环
重复...
#include <string>#include <iostream>using namespace std;string convert(string s,int nRows){ if(nRows==1) return s; string res[nRows]; int i==0,j,gap=nRows-2; while(i<s.size()){ for(j=0;j<nRows && i<s.size();j++) res[j]+=s[i++]; for(j=gap;j>0 && i<s.size();j--) res[j]+=s[i++]; } string ret=""; for(i=0;i<nRows;i++){ ret+=res[i]; } return ret;}
ZigZag-LeetCode
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