首页 > 代码库 > HDU 5053 the Sum of Cube
HDU 5053 the Sum of Cube
题意 求给定区间[a,b] 所有整数的立方和 0<a,b<=10000
注意10000^3会爆int
#include<cstdio>
using namespace std;
typedef long long ll;
int main()
{
int cas;
ll a, b, ans;
scanf("%d", &cas);
for(int k = 1; k <= cas; ++k)
{
ans = 0;
scanf("%I64d%I64d", &a, &b);
for(ll i = a; i <= b; ++i)
ans += i * i * i;
printf("Case #%d: %I64d\n", k, ans);
}
return 0;
}
the Sum of Cube
Problem Description
A range is given, the begin and the end are both integers. You should sum the cube of all the integers in the range.
Input
The first line of the input is T(1 <= T <= 1000), which stands for the number of test cases you need to solve.
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].
Each case of input is a pair of integer A,B(0 < A <= B <= 10000),representing the range[A,B].
Output
For each test case, print a line “Case #t: ”(without quotes, t means the index of the test case) at the beginning. Then output the answer – sum the cube of all the integers in the range.
Sample Input
2 1 3 2 5
Sample Output
Case #1: 36 Case #2: 224
Source
2014 ACM/ICPC Asia Regional Shanghai Online
HDU 5053 the Sum of Cube
声明：以上内容来自用户投稿及互联网公开渠道收集整理发布，本网站不拥有所有权，未作人工编辑处理，也不承担相关法律责任，若内容有误或涉及侵权可进行投诉： 投诉/举报 工作人员会在5个工作日内联系你，一经查实，本站将立刻删除涉嫌侵权内容。