首页 > 代码库 > leetcode - Flatten Binary Tree to Linked List
leetcode - Flatten Binary Tree to Linked List
Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1 / 2 5 / \ 3 4 6The flattened tree should look like:
1 2 3 4 5 6
click to show hints.
Hints:
If you notice carefully in the flattened tree, each node‘s right child points to the next node of a pre-order traversal.
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ struct TreeNode { int val; TreeNode *left; TreeNode *right; TreeNode(int x) : val(x), left(NULL), right(NULL) {} }; class Solution { public: void flatten(TreeNode *root) { if(root == NULL) return; while(root != NULL) { if(root->left != NULL) { TreeNode *p = root->left; while(p->right != NULL) { p = p->right; } p->right = root->right; root->right = root->left; root->left = NULL; } root = root->right; } } };
leetcode - Flatten Binary Tree to Linked List
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。