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[LeetCode] Flatten Binary Tree to Linked List

Given a binary tree, flatten it to a linked list in-place.

For example, Given

         1        /        2   5      / \        3   4   6

 

The flattened tree should look like:

   1         2             3                 4                     5                         6
Hints:

If you notice carefully in the flattened tree, each node‘s right child points to the next node of a pre-order traversal.

/** * Definition for binary tree * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public:    void flatten(TreeNode *root) {        if(root==NULL)            return;        TreeNode *p = root;        Recur(p);    }private:    void Recur(TreeNode *p){        if(p==NULL)            return;        TreeNode *pleft=p->left;        TreeNode *pright = p->right;        p->left = NULL;        p->right = pleft;        Recur(pleft);        while(pleft){//找到pleft的最末点           p = pleft;           pleft = pleft->right;        }        p->right = pright;        Recur(pright);    }};