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BZOJ 4800 折半暴搜

思路:

把它拆成两半  分别搜一发

两部分分别排好序

用two-pointers扫一遍 就可以了.

(读入也要用long long)

//By SiriusRen#include <cstdio>#include <cstring>#include <algorithm>using namespace std;typedef long long ll;int n,len,top,f,r;ll m,s[1500500],s2[1500500],a[55],ans;void dfs(int x,ll wei){    if(wei>m)return;    s[top++]=wei;    for(int i=x+1;i<=len;i++){        dfs(i,wei+a[i]);    }}int main(){    scanf("%d%lld",&n,&m);    for(int i=1;i<=n;i++)scanf("%lld",&a[i]);    len=n/2;    dfs(0,0);    sort(s+1,s+top),r=top-1;    for(int i=1;i<top;i++)s2[i]=s[i];    top=0;len=n;dfs(n/2,0);    sort(s+1,s+top);    for(int i=0;i<top;i++){        while(s[i]+s2[r]>m)r--;        ans+=r+1;    }    printf("%lld\n",ans);}

 

BZOJ 4800 折半暴搜