首页 > 代码库 > Find Minimum in Rotated Sorted Array
Find Minimum in Rotated Sorted Array
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
).
Find the minimum element.
You may assume no duplicate exists in the array.
答案
public class Solution { int []num; public int findMin(int start,int end) { if(num[start]<=num[end]) { return num[start]; } int middle=start+((end-start)>>1); if(num[middle]>num[end]) { return findMin(middle+1,end); } return findMin(start,middle); } public int findMin(int[] num) { this.num=num; return findMin(0,num.length-1); } }
Find Minimum in Rotated Sorted Array
声明:以上内容来自用户投稿及互联网公开渠道收集整理发布,本网站不拥有所有权,未作人工编辑处理,也不承担相关法律责任,若内容有误或涉及侵权可进行投诉: 投诉/举报 工作人员会在5个工作日内联系你,一经查实,本站将立刻删除涉嫌侵权内容。